SOLUTION: I have the parabola ___ y=√x-4 (principal square root) ____ x=√y-9 How do I graph these and find out if it opens to the left, right, up, down also what qua
![The region under the curve y=sqrtx bounded by 0<=x<=4 is rotated about a) the x axis and b) the y axis. How do you sketch the region and find the volumes of The region under the curve y=sqrtx bounded by 0<=x<=4 is rotated about a) the x axis and b) the y axis. How do you sketch the region and find the volumes of](https://useruploads.socratic.org/vTmp53bvR0SGubZomlOb_desmos-graph.png)
The region under the curve y=sqrtx bounded by 0<=x<=4 is rotated about a) the x axis and b) the y axis. How do you sketch the region and find the volumes of
![Draw the region bounded by the curves y=sqrt(x), x=4, y=0. Use the washer method to find the volume - YouTube Draw the region bounded by the curves y=sqrt(x), x=4, y=0. Use the washer method to find the volume - YouTube](https://i.ytimg.com/vi/smMjZPgCaec/maxresdefault.jpg)
Draw the region bounded by the curves y=sqrt(x), x=4, y=0. Use the washer method to find the volume - YouTube
![Let R be the region bounded by y = sqrt(x), y = 0, and x = 4. Use the shell method to find the volume of the solid generated when R is Let R be the region bounded by y = sqrt(x), y = 0, and x = 4. Use the shell method to find the volume of the solid generated when R is](https://homework.study.com/cimages/multimages/16/sqrtroon_041020186047359837321723857.png)
Let R be the region bounded by y = sqrt(x), y = 0, and x = 4. Use the shell method to find the volume of the solid generated when R is
![Find the volume of the solid generated by revolving the region bounded by the graph of the equation about the indicated lines. y = square root x, y = 0, x = Find the volume of the solid generated by revolving the region bounded by the graph of the equation about the indicated lines. y = square root x, y = 0, x =](https://homework.study.com/cimages/multimages/16/graph_of_region_r871378388095815996.png)
Find the volume of the solid generated by revolving the region bounded by the graph of the equation about the indicated lines. y = square root x, y = 0, x =
![The graph of y = \sqrt{4x - x^{2}} is given. Use transformations to create a function whose graph is as shown below. | Homework.Study.com The graph of y = \sqrt{4x - x^{2}} is given. Use transformations to create a function whose graph is as shown below. | Homework.Study.com](https://homework.study.com/cimages/multimages/16/gr30847089449824363178.png)
The graph of y = \sqrt{4x - x^{2}} is given. Use transformations to create a function whose graph is as shown below. | Homework.Study.com
![How do you find the volume of the region bounded by y=sqrt x, y=0, x=0, and x=4 is revolved about the x-axis? | Socratic How do you find the volume of the region bounded by y=sqrt x, y=0, x=0, and x=4 is revolved about the x-axis? | Socratic](https://useruploads.socratic.org/EDRJYhxaSIuYTmNE5oiR_paint.jpg)
How do you find the volume of the region bounded by y=sqrt x, y=0, x=0, and x=4 is revolved about the x-axis? | Socratic
![Sketch the region `{(x, 0):y=sqrt(4-x^(2))}` and X-axis. Find the area of the region using - YouTube Sketch the region `{(x, 0):y=sqrt(4-x^(2))}` and X-axis. Find the area of the region using - YouTube](https://i.ytimg.com/vi/D0AExF76wn8/maxresdefault.jpg)
Sketch the region `{(x, 0):y=sqrt(4-x^(2))}` and X-axis. Find the area of the region using - YouTube
![Sketch the region `{(x, 0):y=sqrt(4-x^(2))}` and X-axis. Find the area of the region using integr - YouTube Sketch the region `{(x, 0):y=sqrt(4-x^(2))}` and X-axis. Find the area of the region using integr - YouTube](https://i.ytimg.com/vi/YXg1plggDDo/maxresdefault.jpg)