![x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)/a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca) - YouTube x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)/a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca) - YouTube](https://i.ytimg.com/vi/-hhSxMp_AjI/maxresdefault.jpg)
x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)/a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca) - YouTube
If x + y + z = 10, xy + yz + zx = -15 and xyz = – 12, then find the values of (i) x^3 + y^3 + z^3 and (ii) x^2 + y^2 + z^2 - Sarthaks eConnect | Largest Online Education Community
![Using Identity VIII x3+y3+z3-3xyz= (x+y+z)(x2+y2+z2-xy-yz-zx) solve the following question 8x3+y3+27z3-18xyz - Maths - Polynomials - 14387709 | Meritnation.com Using Identity VIII x3+y3+z3-3xyz= (x+y+z)(x2+y2+z2-xy-yz-zx) solve the following question 8x3+y3+27z3-18xyz - Maths - Polynomials - 14387709 | Meritnation.com](https://s3mn.mnimgs.com/img/shared/content_ck_images/ck_5e8e92a6ac9c2.jpg)
Using Identity VIII x3+y3+z3-3xyz= (x+y+z)(x2+y2+z2-xy-yz-zx) solve the following question 8x3+y3+27z3-18xyz - Maths - Polynomials - 14387709 | Meritnation.com
![Using the identity and proof: x^3 + y^3 + z^3 - 3xyz = (x + y + z)(x^2 + y^2 + z^2 - xy - yz - zx) . Using the identity and proof: x^3 + y^3 + z^3 - 3xyz = (x + y + z)(x^2 + y^2 + z^2 - xy - yz - zx) .](https://haygot.s3.amazonaws.com/questions/1939669_1152866_ans_242631d625f34fc98fe0cb4bd8931f18.jpg)
Using the identity and proof: x^3 + y^3 + z^3 - 3xyz = (x + y + z)(x^2 + y^2 + z^2 - xy - yz - zx) .
![x+y)3 + ( y + z)3 + ( z+x)3 - 3(x+y)(y+z)(z+x) = 2 ( x3 + y3 + z3 - 3xyz) - CBSE Class 9 Maths - Learn CBSE Forum x+y)3 + ( y + z)3 + ( z+x)3 - 3(x+y)(y+z)(z+x) = 2 ( x3 + y3 + z3 - 3xyz) - CBSE Class 9 Maths - Learn CBSE Forum](https://ask.learncbse.in/uploads/db3785/original/3X/9/2/92de191c3d8df278b9ed220641d503aba418e7cf.png)