![If A = {3, 6, 9, 12, 15, 18, 21}, B = { 4, 8, 12, 16, 20 }, C = { 2, 4, 6, 8, 10, 12, 14, 16 }, D = { If A = {3, 6, 9, 12, 15, 18, 21}, B = { 4, 8, 12, 16, 20 }, C = { 2, 4, 6, 8, 10, 12, 14, 16 }, D = {](https://i.ytimg.com/vi/UaZtd1w45P4/maxresdefault.jpg)
If A = {3, 6, 9, 12, 15, 18, 21}, B = { 4, 8, 12, 16, 20 }, C = { 2, 4, 6, 8, 10, 12, 14, 16 }, D = {
![Prove that (a+b+c)3 - a3 - b3 - c3 = 3(a+b)(b+c)(c+a) - Maths - Polynomials - 9459241 | Meritnation.com Prove that (a+b+c)3 - a3 - b3 - c3 = 3(a+b)(b+c)(c+a) - Maths - Polynomials - 9459241 | Meritnation.com](https://s3mn.mnimgs.com/img/shared/discuss_editlive/4123606/2013_02_23_18_16_18/mathmlequation8803507640036004166.png)
Prove that (a+b+c)3 - a3 - b3 - c3 = 3(a+b)(b+c)(c+a) - Maths - Polynomials - 9459241 | Meritnation.com
![x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)/a^3+b^3+c^3-3abc=(a+b+c)(a^2+ b^2+c^2-ab-bc-ca) - YouTube x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)/a^3+b^3+c^3-3abc=(a+b+c)(a^2+ b^2+c^2-ab-bc-ca) - YouTube](https://i.ytimg.com/vi/-hhSxMp_AjI/maxresdefault.jpg)
x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)/a^3+b^3+c^3-3abc=(a+b+c)(a^2+ b^2+c^2-ab-bc-ca) - YouTube
![a^3+b^3+c^3-3abc formula | (a+b)^2=a^2+b^2+2ab Proof | Derivation of Algebraic Identities - YouTube - YouTube a^3+b^3+c^3-3abc formula | (a+b)^2=a^2+b^2+2ab Proof | Derivation of Algebraic Identities - YouTube - YouTube](https://i.ytimg.com/vi/axRla6uwnaM/maxresdefault.jpg)